Packets per second crossing an interface?

The following is a method you can use to determine the number of packets per second crossing an interface. The example interface used is eth-s1p1: nokia[admin]# netstat –i | grep eth-s1p1; sleep 10; netstat –i | grep eth-s1p1 Name        Mtu   Network    Address            Ipkts Ierrs    Opkts Oerrs  Coll eth-s1p1     9600      0:a0:8e:70:fd:48 3254126830     0 1488520554  eth-s1p1     9600      0:a0:8e:70:fd:48 3254399730     0 1488822824  What the preceding command does is output two lines: the number of packets the interface has seen when the command is first executed, and the number of packets seen 10 seconds later. Given that information, we can deduce the number of packets per second, both coming into and going out of the box. As you see there are 2 columns for each interface after the MAC address.  The first column input packets, the second is out packets.  To figure out total:   ((3254399730–3254126830)/10)+((1488822824–1488520554)/10) = 57517 packets Here is how you find packets per second and bytes per second nokia[admin]# netstat -ib | grep eth-s1p1; sleep 10; netstat -ib | grep eth-s1p1 Name        Mtu   Network    Address            Ipkts Ierrs     Ibytes    Opkts Oerrs     Obytes  Coll eth-s1p1     9600      0:a0:8e:70:fd:48 3286824714     0 3134996150 1524566033     0  703331799     0 eth-s1p1     9600      0:a0:8e:70:fd:48 3287099394     0 3335905031 1524872800    0  867944108     0 Packets per second – to find total add both Ipkts and Opkts ((3287099394-3286824714)/10)+((1524872800-1524566033)/10)= 58144 Bytes per second - to find total add both Ibytes and Obytes ((3335905031-3134996150)/10)+((867944108-703331799)/10)= 36552118 bytes To get your average packet size divide bytes by packets